Friday, September 12, 2008
12th september Gre Quants Question
Col A: (-2)^((n+1)/2)
Col B: (-2)^((n-1)/2)
2.
Given equation of the parabola as y = 2x-x^2.
Col A: t
Col B: 2s-s^2
3. A person has 5 pairs of sox and each are differently colored. If a person picks one pair of sox simultaneously, what is the probability that it is of same colored pair?
4. How many different 5 digit numbers can formed, such that 1st and last place should be filled up with odd number.
A.25000
B.20000
so on….
5. If (4/7) = (4+s)/(7+t), then
Col A: s
Col B: (4t/7)
6. If x(x-15/7)(x+4)(x+3)=0, then what is the product of maximum and minimum value of x?
7. If a square of 125cm3 is fit into a cylinder, then what should be the minimum value of the volume of the cylinder?
8. If (a^2 @ b^2) = a^2-b^2 & (a^2 # b^2) = a^2+b^2, then
Col A: (2^2@-2^2) # (3^2@-3^2)
Col B: 0
9. The Harmonic Mean of 10, 20 is ………..
Friday, September 12, 2008
12th september Gre Quants Question
Col A: (-2)^((n+1)/2)
Col B: (-2)^((n-1)/2)
2.
Given equation of the parabola as y = 2x-x^2.
Col A: t
Col B: 2s-s^2
3. A person has 5 pairs of sox and each are differently colored. If a person picks one pair of sox simultaneously, what is the probability that it is of same colored pair?
4. How many different 5 digit numbers can formed, such that 1st and last place should be filled up with odd number.
A.25000
B.20000
so on….
5. If (4/7) = (4+s)/(7+t), then
Col A: s
Col B: (4t/7)
6. If x(x-15/7)(x+4)(x+3)=0, then what is the product of maximum and minimum value of x?
7. If a square of 125cm3 is fit into a cylinder, then what should be the minimum value of the volume of the cylinder?
8. If (a^2 @ b^2) = a^2-b^2 & (a^2 # b^2) = a^2+b^2, then
Col A: (2^2@-2^2) # (3^2@-3^2)
Col B: 0
9. The Harmonic Mean of 10, 20 is ………..
18 comments:
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Anonymous said...
-
1.D
2.B
3.1/9
4.6720
5.C
6.-60/7
7.98.214
8.C
9.40/3
Please check the quant database for the diagram of the 2nd Question
Please correct me if iam wrong anywhere -
September 14, 2008 at 12:23 PM
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Anonymous said...
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hey can u explain how did u solve 7th question ??
-
September 14, 2008 at 12:24 PM
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Anonymous said...
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Hi chirag,
for the 7th question.....square with 125cubic cm is cube.
For the cube to fit in the cylinder, the diameter of the cylinder should atleast be 5 and the height of the cylinder should atleast be 5
Therefore, r=2.5 and h=5
Minimum volume of a cylinder = pie * r^2*h
=3.14*(2.5^2)*5=98.214
Please correct me if iam wrong anywhere -
September 14, 2008 at 12:24 PM
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Anonymous said...
-
Hi chirag,
i made a mistake
the diameter of the cylinder should atleast be the diagonal of the square
Diameter= 5(sqrt2)
radius=5/(sqrt2)
Volume=3.14*(25/2)*5 = 196.43
Please let me know in case of any Issues -
September 14, 2008 at 12:24 PM
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Anonymous said...
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can anyone explain me the second ques briefly...
i am obfuscated..... -
September 14, 2008 at 12:25 PM
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Anonymous said...
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Hi pradeey,
from the diagram,
y=2x-x^2 only at the apex of the parabola...for all the points inside the parabola,,,y will be less than 2x-x^2
Given point (s,t) is inside the parabola,
Therefore,t < 2s-s^2
Answer is B
Please let me know in case of any issues -
September 14, 2008 at 12:25 PM
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Anonymous said...
-
if a cube is to fit into a cylinder, the min height of cylinder must be equal to height of cube=5
where as the radius of cylinder on top surface must be half of hypotenuse of square surface of cube, hypotenuse=5*sqrt(2)
r=5*sqrt(2)/2=7.07/2=3.535,
vol of cylinder=pie*r^2*h,=196.19 -
September 14, 2008 at 12:25 PM
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Anonymous said...
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question no 4 answer is 25000
there are five places to b filled _ _ _ _ _
first and last places can b filled in five ways 5*5(ie 1,3,5,7,9)
second third and fourth places can be filled in 10 ways (0,1,2.....9)
therefore the answer is 5 * 10 * 10 * 10 * 5
=25000 -
September 14, 2008 at 12:26 PM
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Anonymous said...
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pls explain 9 th question
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September 14, 2008 at 12:26 PM
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Anonymous said...
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Hi senthil,
for the 9th question
HM = 2/((1/a)+(1/b))
Use this formula,u vl get the answer
Please correct me if iam wrong -
September 14, 2008 at 12:26 PM
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Ganta Pothuluri Reddy said...
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please solve 3rd ?...i am confused
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September 15, 2008 at 2:42 AM
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Shekhar Agrawal said...
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Hi Ganta
For Ques 3rd
There are 5 pairs , i.e. 10 socks. You have picked 2.
Lets start solving ::::::
For first pick, you have 10 socks. (No need to find probability for this move, bcoz you have been told to pick two socks of same colour and not socks of a specific color).
Second move:: Now u have a sox of a color. U ve 9 socks remaining wid you. So, since dere are 5 pairs each of different color, and u ve picked one sox, so out of remaining 9 sox, dere's only 1 sox wic is of same color wic u ve picked. Thus desired event/total event = 1/9 -
September 15, 2008 at 4:24 AM
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Shekhar Agrawal said...
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Hi..
What about Ques 6.
I am trying with Single and double differtiation method, but it's getting lengthy.
Is dere any direct method to find the product of maxima and minima -
September 15, 2008 at 4:48 AM
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Shekhar Agrawal said...
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Hi
For Ques 8.
If
(a^2 @ b^2) = a^2-b^2
(a^2 # b^2) = a^2+b^2
then
Col A: (2^2@-2^2) # (3^2@-3^2)
Col B: 0
Sol:::::::::
(2^2@-2^2) = (2^2 + 2^2) = 8
(3^2@-3^2) = (9 + 9) = 18
8#18 = 8+18 = 26 >0
so, answer shud be 'A'
Please correct me if I am wrong. Look the other 2 posts also -
September 15, 2008 at 5:01 AM
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Lite said...
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hi,
for 2nd question i guess as (s,t) are abscissa and ordinates of same point, while implementing the formula we get Col A and Col B equal -
September 15, 2008 at 10:07 AM
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Shruthi said...
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the ans for 9th
H.M = n/(1/x1+1/x2)
= 2/(1/10+1/20)
= 40/3 -
September 16, 2008 at 1:01 AM
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Anonymous said...
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i think the answer for the 2nd question is D,as the point is not on the curve (s,t) cannot be determined
---please correct me if i am wrong -
September 16, 2008 at 2:18 AM
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Anonymous said...
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VICKY,
BRO.. PLZ UPDATE IT I HAVE MY EXAM ON 21 OF THIS MONTH.
PLZ PLA PLZ -
September 18, 2008 at 3:46 PM
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18 comments:
1.D
2.B
3.1/9
4.6720
5.C
6.-60/7
7.98.214
8.C
9.40/3
Please check the quant database for the diagram of the 2nd Question
Please correct me if iam wrong anywhere
hey can u explain how did u solve 7th question ??
Hi chirag,
for the 7th question.....square with 125cubic cm is cube.
For the cube to fit in the cylinder, the diameter of the cylinder should atleast be 5 and the height of the cylinder should atleast be 5
Therefore, r=2.5 and h=5
Minimum volume of a cylinder = pie * r^2*h
=3.14*(2.5^2)*5=98.214
Please correct me if iam wrong anywhere
Hi chirag,
i made a mistake
the diameter of the cylinder should atleast be the diagonal of the square
Diameter= 5(sqrt2)
radius=5/(sqrt2)
Volume=3.14*(25/2)*5 = 196.43
Please let me know in case of any Issues
can anyone explain me the second ques briefly...
i am obfuscated.....
Hi pradeey,
from the diagram,
y=2x-x^2 only at the apex of the parabola...for all the points inside the parabola,,,y will be less than 2x-x^2
Given point (s,t) is inside the parabola,
Therefore,t < 2s-s^2
Answer is B
Please let me know in case of any issues
if a cube is to fit into a cylinder, the min height of cylinder must be equal to height of cube=5
where as the radius of cylinder on top surface must be half of hypotenuse of square surface of cube, hypotenuse=5*sqrt(2)
r=5*sqrt(2)/2=7.07/2=3.535,
vol of cylinder=pie*r^2*h,=196.19
question no 4 answer is 25000
there are five places to b filled _ _ _ _ _
first and last places can b filled in five ways 5*5(ie 1,3,5,7,9)
second third and fourth places can be filled in 10 ways (0,1,2.....9)
therefore the answer is 5 * 10 * 10 * 10 * 5
=25000
pls explain 9 th question
Hi senthil,
for the 9th question
HM = 2/((1/a)+(1/b))
Use this formula,u vl get the answer
Please correct me if iam wrong
please solve 3rd ?...i am confused
Hi Ganta
For Ques 3rd
There are 5 pairs , i.e. 10 socks. You have picked 2.
Lets start solving ::::::
For first pick, you have 10 socks. (No need to find probability for this move, bcoz you have been told to pick two socks of same colour and not socks of a specific color).
Second move:: Now u have a sox of a color. U ve 9 socks remaining wid you. So, since dere are 5 pairs each of different color, and u ve picked one sox, so out of remaining 9 sox, dere's only 1 sox wic is of same color wic u ve picked. Thus desired event/total event = 1/9
Hi..
What about Ques 6.
I am trying with Single and double differtiation method, but it's getting lengthy.
Is dere any direct method to find the product of maxima and minima
Hi
For Ques 8.
If
(a^2 @ b^2) = a^2-b^2
(a^2 # b^2) = a^2+b^2
then
Col A: (2^2@-2^2) # (3^2@-3^2)
Col B: 0
Sol:::::::::
(2^2@-2^2) = (2^2 + 2^2) = 8
(3^2@-3^2) = (9 + 9) = 18
8#18 = 8+18 = 26 >0
so, answer shud be 'A'
Please correct me if I am wrong. Look the other 2 posts also
hi,
for 2nd question i guess as (s,t) are abscissa and ordinates of same point, while implementing the formula we get Col A and Col B equal
the ans for 9th
H.M = n/(1/x1+1/x2)
= 2/(1/10+1/20)
= 40/3
i think the answer for the 2nd question is D,as the point is not on the curve (s,t) cannot be determined
---please correct me if i am wrong
VICKY,
BRO.. PLZ UPDATE IT I HAVE MY EXAM ON 21 OF THIS MONTH.
PLZ PLA PLZ
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