Thursday, September 11, 2008

11th September Gre Quants Question

1.

If the radius of the larger circle is twice the radius of smaller circle, then find how many times is the shaded region greater than unshaded region?

2. The Value of 0.00004/40000 is.........

3. If x < 0, then
Col A: |x|
Col B: -x

4. Col A: 0.01/1- 0.01
Col B: 0.1/1- 0.1

5. If x is a negative number, then
Col A: mod x + mod(-2)
Col B: mod(x-2)

6. If 6 < 2x < 12 and 4 < x < 7, then
Col A: x
Col B: 5

7. The coordinates ends of base of a square are given, and were asked to find the side of the square?
(Question is similar to this)

8. Given one coordinate of the edge of a square is (3/2, 3/2). What is the equation of the diagonal of a square?

9. Col A: 10^12+2^12
Col B: 12^12

10. If the area of one square is 44% more than that of other square, then by what percentage the side is differed?

11. There is a parabola whose equation was y = 2x-x^2. The parabola was drawn such that, the curvy part was in the first quadrant.. and now if (s, t) is any point between positive x-axis and the curve
Col A: t
Col B: 2s-s^2

12. Given:
Value (in cents) - Quantity
5 - x
10 - y
15 - z
If the number of 5 cents coins were equal to number of 10 cents coins and if the total number of coins in the bag were 17 and their total value was 258 cents then how would you calculate the number of 5 cent coins?


answers to Sept 11 thread :
1.4
2.(10)^-9
3.C
4.B
5.C
6.D
7.Use distance formula
8.y=x
9.B
10.20%
11.B
12.?

if there are any issues please let me know.

10 comments:

Anonymous said...

for the 10 th one
just assume some value for side let it be 10
so area is 100
44% of 100 is 44
so new area is 44+100=144
so side of new area is root 144=12
12/10*100=120 that is 100%+20new one
so 20 %
hope u understand if i am not confusing u...!!

Anonymous said...

hey...answer to question 1

assume the radius of the smaller circle R then its area is pie R^2
now the radius of the bigger circle is double the smaller hence 2R
therefore its area will be 4*pie*R^2

therefore area of the shaded region will be = 4*pie*R^2 - pieR^2= 3* pie* R^2

therefore area of the shaded region is 3 times that of the unshaded regoin..

Anonymous said...

for question 1..
assume ,
area of larger circle=(m times)area of smaller circle.

so,4*pie*R^2 =(m) pie* R^2

so m= (4*pie*R^2)/(pie* R^2)

so,m=4

Unknown said...

swapna
pls explan me 3 & 6

Shekhar Agrawal said...

Hi Sanket.

Your expanation is correct but mistakenly you have calculated ratio of areas of larger and smaller circles. Question asks to find ratio of shaded and unshaded region.. It's 3

Shekhar Agrawal said...

Hey

Ques 4:

0.01/1 - 0.01 = 0.01 - 0.01 = 0
0.1/1 - 0.1 = 0.1 - 0.1 = 0

You don't need to calculate all this. anynumber divided by 1 is that number only
Answer : C

Anonymous said...

@shekhar

oh yes..thnkx for correcting me..

Anonymous said...

given that x<0
and we have to find |x|
i.e) x is always taken as +ve since | | of any value is +ve
and -ve of -ve value is +ve
so
|x| = -(x) when 'x' is -ve

Anonymous said...

sorry in this google we con't use graterthan and lessthan
so
given that range of 2x (6,12) range of x (4,7)
in this
first find 'x' range in (6,12)
=> 6/2 x 12/2
=> 3 x 6 AND GIVEN 4 x 7
so 'x' value not lessthan 3,4 and not grater than 6,7
so x is in between them it may be 4.0000....1 to 6.999999.....
so 'x' may lessthan 5 if x is 4.000... may grater if x is 5.0000...
so we con't say about x and 5
option is D

Unknown said...

Can anybody explain number 5.?

what does the MOD x mean here?

if you're allowed to do mod (negative), adding mod(-2) will be a maximum of 1. Since mod (x-2) will result in maximum increase of 2 to the remainder, wouldn't B or D be a better answer?

Thursday, September 11, 2008

11th September Gre Quants Question

1.

If the radius of the larger circle is twice the radius of smaller circle, then find how many times is the shaded region greater than unshaded region?

2. The Value of 0.00004/40000 is.........

3. If x < 0, then
Col A: |x|
Col B: -x

4. Col A: 0.01/1- 0.01
Col B: 0.1/1- 0.1

5. If x is a negative number, then
Col A: mod x + mod(-2)
Col B: mod(x-2)

6. If 6 < 2x < 12 and 4 < x < 7, then
Col A: x
Col B: 5

7. The coordinates ends of base of a square are given, and were asked to find the side of the square?
(Question is similar to this)

8. Given one coordinate of the edge of a square is (3/2, 3/2). What is the equation of the diagonal of a square?

9. Col A: 10^12+2^12
Col B: 12^12

10. If the area of one square is 44% more than that of other square, then by what percentage the side is differed?

11. There is a parabola whose equation was y = 2x-x^2. The parabola was drawn such that, the curvy part was in the first quadrant.. and now if (s, t) is any point between positive x-axis and the curve
Col A: t
Col B: 2s-s^2

12. Given:
Value (in cents) - Quantity
5 - x
10 - y
15 - z
If the number of 5 cents coins were equal to number of 10 cents coins and if the total number of coins in the bag were 17 and their total value was 258 cents then how would you calculate the number of 5 cent coins?


answers to Sept 11 thread :
1.4
2.(10)^-9
3.C
4.B
5.C
6.D
7.Use distance formula
8.y=x
9.B
10.20%
11.B
12.?

if there are any issues please let me know.

10 comments:

Anonymous said...

for the 10 th one
just assume some value for side let it be 10
so area is 100
44% of 100 is 44
so new area is 44+100=144
so side of new area is root 144=12
12/10*100=120 that is 100%+20new one
so 20 %
hope u understand if i am not confusing u...!!

Anonymous said...

hey...answer to question 1

assume the radius of the smaller circle R then its area is pie R^2
now the radius of the bigger circle is double the smaller hence 2R
therefore its area will be 4*pie*R^2

therefore area of the shaded region will be = 4*pie*R^2 - pieR^2= 3* pie* R^2

therefore area of the shaded region is 3 times that of the unshaded regoin..

Anonymous said...

for question 1..
assume ,
area of larger circle=(m times)area of smaller circle.

so,4*pie*R^2 =(m) pie* R^2

so m= (4*pie*R^2)/(pie* R^2)

so,m=4

Unknown said...

swapna
pls explan me 3 & 6

Shekhar Agrawal said...

Hi Sanket.

Your expanation is correct but mistakenly you have calculated ratio of areas of larger and smaller circles. Question asks to find ratio of shaded and unshaded region.. It's 3

Shekhar Agrawal said...

Hey

Ques 4:

0.01/1 - 0.01 = 0.01 - 0.01 = 0
0.1/1 - 0.1 = 0.1 - 0.1 = 0

You don't need to calculate all this. anynumber divided by 1 is that number only
Answer : C

Anonymous said...

@shekhar

oh yes..thnkx for correcting me..

Anonymous said...

given that x<0
and we have to find |x|
i.e) x is always taken as +ve since | | of any value is +ve
and -ve of -ve value is +ve
so
|x| = -(x) when 'x' is -ve

Anonymous said...

sorry in this google we con't use graterthan and lessthan
so
given that range of 2x (6,12) range of x (4,7)
in this
first find 'x' range in (6,12)
=> 6/2 x 12/2
=> 3 x 6 AND GIVEN 4 x 7
so 'x' value not lessthan 3,4 and not grater than 6,7
so x is in between them it may be 4.0000....1 to 6.999999.....
so 'x' may lessthan 5 if x is 4.000... may grater if x is 5.0000...
so we con't say about x and 5
option is D

Unknown said...

Can anybody explain number 5.?

what does the MOD x mean here?

if you're allowed to do mod (negative), adding mod(-2) will be a maximum of 1. Since mod (x-2) will result in maximum increase of 2 to the remainder, wouldn't B or D be a better answer?