5th november Gre Quants Question

1. What is the range of numbers between 400 and 700 that are divisible by 2 and 3?

2. Col A: x^2 + y^2
Col B: (x + 1)^2 * (y + 1)^2

3. Given a series p1, p2, p3, p4................ If p1 = 1 & pn = 24*p(n-1)+8, then
Col A: The remainder when p66 is divided by 6
Col B: 4
(Here 1, 2, 3, 4, 66, n & n-1 are suffixes)

4. If 1pen & 1stapler costs 12.50$ and 3pens & 2staplers costs 25$, then
Col A: Cost of 1pen
Col B: 4.20$

5. Given a circle in the coordinate system with centre at (3, 4), find the radius of the circle?

6. Given average of a & b as 10. When 'c' is added to a & b, then the average is 10(again).
Col A: Value of 'c'
Col B: 10

7. If -1 < x < 0, then which of the following will have greater value?
A.0.8x
B. 1/sqrt(x)
C. (5x)/6
D. sqrt(x)
& so on......

8.


Col A: a^2 + b^2 + c^2
Col B: f^2

Answers and Explanations

1. 51. Since the question asks for both divisible by 2 and 3. We need to find the numbers divisible by 6. Now 402 is the first number in the range that is divisible by 6. Starting from 402 there are 17 numbers in the range 400 to 500 divisible by 6. 17 again in 500 to 600 as well as 600 to 700. So the answer is 17*3= 51

2. Relationship cannot be determined. take x and y 0 and take x and y -1 and test.

3. Col B is greater. because the first term is Pn is multiplied by 24 so it will give remainder 0 when divided by 6 but the +8 in the end will give remainder 2.

However P66 = 24^66 + 8*24^65 + 8*24^64 + .... + 8*24 + 8

4. I think the answer is Col B is greater. its given that 1pen & 1stapler costs $12.50 which means 2pen & 2stapler costs $25. But its also given that 3pens & 2staplers costs $25. his is only possible when pens are given for free i.e. zero cost.

5. Radius of the circle cannon be found just from the center

6. Col A and Col B are equal

7. based on the given options the answer is A. As 5/6 is .83 and B and D are not feasible as complex number is not in GRE syllabus.

8. Both Cols are equal.